Simple Roman Numeral Conversion in Python

For Example, We like to convert CCXCIV to 294

# Mapping of Roman Numerals to English Digits is like this

I=1

V=5

X=10

L=50

C=100

D=500

M=1000

# We can use Dictionary in Python

R={'I':1,'V':5,'X':10,'L':50,'C':100,'D':500,'M':1000}

# Actual Function to sum up the values for each roman numerals, in a line

roman=lambda x:reduce(lambda T,x:T+R[x]-T%R[x]*2,x,0)

In python, there is reduce function, that can do [1,2,3,4] => 10, 

by summing up from left to right like this (((1+2)+3)+4)

The correct answer should be , C=100, C=100, XC=90, IV=4 => 294

But when we sum up XC, X=10, C=100, oh, its becomes 110, and actual one should be 90.

No worries, 110 is the 90 + 20, and 20 is 2 times of X, isnt it? so just substract it after you sum up :-)

-T%R[x]*2 will do it for you, got it? IV will do same as 6 - 2 => 4 too :-)

so 200 + 90 + 4 will be 294 :-)

Thats the idea I got today, may be somebody already done like that before, but I can't find anything like this in Google, so this is mine.

You can download full program here at my google code page, the license for that is MIT License.

http://soemin.googlecode.com/files/roman.py

Here is the some of the test results

I 1 1 True

II 2 2 True

III 3 3 True

IV 4 4 True

V 5 5 True

VI 6 6 True

VII 7 7 True

VIII 8 8 True

IX 9 9 True

X 10 10 True

L 50 50 True

C 100 100 True

D 500 500 True

M 1000 1000 True

XXXI 31 31 True

CXLVIII 148 148 True

CCXCIV 294 294 True

CCCXII 312 312 True

CDXXI 421 421 True

DXXVIII 528 528 True

DCXXI 621 621 True

DCCLXXXII 782 782 True

DCCCLXX 870 870 True

CMXLI 941 941 True

MXLIII 1043 1043 True

# First column is Roman Numerals, 2nd is actual Values, 3rd is generate Results, 4th is checking the Result is Right or Wrong 

Cheers,

Mark